KVPY SA Exam 2015 Question Paper

Question : 33 of 80

Marks: +1, -0

Maximum number of electrons that can be accommodated in the subshell with azimuthal quantum number l = 4, is

Solution:

l = 4 → ‘g’

subshell
∴ no of

e ^{–} = 2 (2l + 1)

= 2(2 × 4 + 1) = 18e^{–}

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