KVPY SA Exam 2015 Question Paper

Question : 29 of 80

Marks: +1, -0

One mole of ideal gas undergoes a linear process as shown in figure below. Its temperature expressed as a function of volume V is,

Solution:

P = P_0-P_0/V_0×V

.....(1)
PV = RT .....(2) (Ideal gas eqs.)
from (1) and (2)

{RT}/V= P_0-P_0/V_0×V

T={P_0V}/R-{P_0V^2}/{RV_0

=P_0/R[V-V^2/V_0]

T={P_0V}/R[1-V /V_0]

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