KVPY SA Exam 2014 Question Paper

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Question : 1 of 80

Marks: +1, -0

PART-I

MATHEMATICS

Let r be a root of the equation

r^ 2 + 2r + 6 = 0

. The valueof

(r + 2)(r + 3)(r + 4)(r + 5)

is equal to

51
-51
-126
12

Solution:

r is root, therefore

r^ 2 + 2r + 6 = 0

(r + 2)(r + 3)(r + 4)(r + 5)

= (r^2 + 2r + 6 + 3r)

(r^2 + 4r + 5r + 20)

= (3r) (7r + 14)

= 21(r^2 + 2r) = 21(- 6)

=- 126

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