KVPY SA Exam 2012 Question Paper

Question : 67 of 80

Marks: +1, -0

A firecracker is thrown with velocity o f 30 m.s

^{-1}

in a direction which makes an angle of 75° with the vertical axis. At some point on its trajectory, the firecracker splits into two identical pieces in such a way that one piece falls 27 m far from the shooting point. Assuming that all trajectories are contained in the same plane, how far will the other piece fall from the shooting point? (Take g = 10 m.s

^{-2}

and neglect air resistance)

63 m or 144 m
72 m or 99 m
28 m or 72 m
63 m or 117 m

Validate

Solution:

Under influence of constant force centre of mass follows its original path

R={30×30×1/2}/10=45\m

45={±m×27+\mx}/{m+m}

x = 63 m, 117 m

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