KVPY SA Exam 2012 Question Paper

A(1, 1);B(2,3);C(5,2);D(3,0)
For Fig 1
$\mathrm{AB}=\sqrt{1+4}=\sqrt{5}$
$\mathrm{BC}=\sqrt{9+1}=\sqrt{10}$
$\mathrm{CD}=\sqrt{4+4}=\sqrt{8}$
then AB + BC +CD = 8.22
For Fig 2
AB = 1; BC = 2; CD $=\sqrt{10}$; DE $=\sqrt{8}$
AB + BC + CD + DE = 8.99
For Fig 3
AB $=\sqrt{5}$; BC = 2; CD $=\sqrt{5}$; DE $=\sqrt{5}$
AB + BC + CD + DE = 8.70
For Fig 4
AB = 1; BC = 2; CD $=\sqrt{13}$; DE $=\sqrt{5}$
AB + BC + CD + DE = 8.841