KVPY SA Exam 2012 Question Paper

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Question : 4 of 80

Marks: +1, -0

If a, b, c, d are positive real numbers such that

a/3={a+b}/4

={a+b+c}/5={a+b+c+d}/6

, then

a/{b+2c+3d}

is

$1/2$
1
2
not determinable

Solution:

a/3={a+b}/4

={a+b+c}/5={a+b+c+d}/6=k

a = 3k, b = k

,

c = k, d = k

Hence

a/{b+2c+3d}

={3k}/{k+2k+3k}=1/2

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