KVPY SA Exam 2012 Question Paper

Question : 16 of 80

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PHYSICS

A clay ball of mass m and speed v strikes another metal ball of same mass m, which is at rest. They stick together after collision. The kinetic energy of the system after collision is

${mv^2}/2$
${mv^2}/4$
$2mv^2$
$mv^2$

Validate

Solution:

Applying the law of conservation of momentum,

mv + 0 = (2m) v'

v' = v/2

K.E.=1/2(2m)v'^2

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