KVPY SA Exam 2011 Question Paper

Question : 75 of 80

Marks: +1, -0

At 783 K in the reaction

H_2 (g) + I_2 (g) ⇌ 2HI (g)

, the molar concentrations (mol I

^{-1}

) of

H_2,I_2

and HI at some instant of time arc 0.1,0.2 and 0.4. respectively. If the equilibrium constant is 46 at the same temperature, then as the reaction proceeds

the amount of HI will increase
the amount of HI will decrease
the amount of $H_2$ and $I_2$ will increase
the amount of $H_2$ and $I_2$ will not change

Validate

Solution:

Reaction quotient

Q=[\HI]/{[\H_2][\I_2]} ={0.4×0.4}/{0.1×0.1}

Q = 8
Q < K
So reaction will proceeds in forward direction.
Hence amount of HI increases.

Go to Question:

Prev Question

Next Question