KVPY SA Exam 2011 Question Paper

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Question : 41 of 80

Marks: +1, -0

The number of P-H bond(s) in

H_3PO_2, H_3PO_3

and

H_3PO_4

, respectively, is

$2,0,1$
$1,1,1$
$2 ,0 ,0$
$2 ,1 ,0$

Solution:

So,

\H_3\PO_2

,

\H_3\PO_3

and

\H_3\PO_4

contains 2, 1 and zero P–H bonds.

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