KVPY SA Exam 2011 Question Paper

Question : 39 of 80

Marks: +1, -0

After 2 hours the amount of a certain radioactive substance reduces to

1/16

th of the original amount (the decay process follows first-order kinetics). The half-life of the radioactive substance is

Solution:

0.693/t_{1\/2}=2.303/{2×60}\log a/{a\/16}

t_{1\/2}

= 30 min

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