KVPY SA Exam 2011 Question Paper

Question : 30 of 80

Marks: +1, -0

The number of air molecules in a (5 m × 5 m × 4 m) room at standard temperature and pressure is of the order of

Solution:

PV = N × K × T
where K is Boltzmann constant

10^5 × 100

= N × 1.38 × 10^{–23} × 273

N ≈ 3 × 10^27

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