KVPY SA Exam 19-Nov-2017 Question Paper

Question : 44 of 80

Marks: +1, -0

A solution (5 mL) of an acid X is completely neutralized by y mL of 1M NaOH. The same volume (y ML) of 1M NaOH is required to neutralize 10 mL of 0.6 M of

H_2SO_4

completely. The normality (N) of the acid X is

Validate

Solution:

(No. of eq.)

_\NaOH

= (No. of eq.)

_{\H_2\SO_4}

⇒

(1×1) × y = (0.6 × 2) × 10

Now, (No. of eq.)

_\acid

= (No. of eq.)

_\NaOH

⇒

N × 5 = (1 × 1) × 12

⇒

N=12/5=2.4

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