KVPY SA Exam 19-Nov-2017 Question Paper

Question : 13 of 80

Marks: +1, -0

Let X,Y,Z be respectively the areas of a regular pentagon, regular hexagon and regular heptagon which are inscribed in a circle of radius 1. Then

Solution:

Area of Pentagon

=5×1/2\sin 72°

=2.377=x

Area of hexagon

=6×1/2\sin 60°

=3×√3/2=2.598=y

Area of heptagon

= 7×1/2\sin 360°/7=2.73 = z

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