KVPY SA Exam 05-Nov-2017 Question Paper

Question : 28 of 80

Marks: +1, -0

A particle starts moving along a line from zero initial velocity and comes to rest after moving distance d.
During its motion it had a constant acceleration f over 2/3 of the distance, and covered the rest of the distance with constant retardation. The time taken to cover the distance is

$√{2d\/ 3f}$
$2 √{d \/ 3f }$
$√{ 3d \/f }$
$√{ 3d \/ 2f}$

Validate

Solution:

a_1 l_ 1 = a_2 l_ 2

by equation of motion Retardation = 2f

t = t_1 + t_2

√{{4d}/{3\f}}+√{{2d}/{2\f}}=√{{3d}/{ \f}}

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