KVPY 2020-21 SB SX Exam Previous Papers

Question : 59 of 120

Marks: +1, -0

A compound is formed by two elements M and N. Element N forms hexagonal closed pack array with 2/3 of the octahedral holes occupied by M.
The formula of the compound is :

$M_4N_3$
$M_2N_3$
$M_3N_2$
$M_3N_4$

Validate

Solution:

Number of atoms of element ‘N’ per unit cell = 6
Number of atoms of element M per unit cell

={2}/{3}

(Number of octahedral voids per unit cell)

={2}/{3} \×6=4

M: N=4: 6=2: 3

Formula is

{M}_{2} {N}_{3}

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