KVPY 2020-21 SB SX Exam Previous Papers

Question : 40 of 120

Marks: +1, -0

A source simultaneously emitting light at two wavelengths

400 {nm}

and

800 {nm}

is used in the Young's double slit experiment. If the intensity of light at the slit for each wavelength is

{I}_{0}

, then the maximum intensity that can be observed at any point on the screen is

Solution:

At central maxima
Due to

400 {nm}=4 {I}_{0}

Due to

800 {nm}=4 {T}_{0}

Total Intensity

=8 {I}_{0}

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