A conducting rod, with a resistor of resistance R, is pulled with constant speed v on a smooth conducting rail as shown in figure. A constant magnetic field B^{\to} is directed into the page. If the speed of the bar is doubled, by what factor does the rate of heat dissipation across the resistance R change ?

KVPY 2020-21 SB SX Exam Previous Papers

Question : 36 of 120

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A conducting rod, with a resistor of resistance R, is pulled with constant speed v on a smooth conducting rail as shown in figure. A constant magnetic field

B↖{→}

is directed into the page.
If the speed of the bar is doubled, by what factor does the rate of heat dissipation across the resistance R change ?

0
$√ 2$
2
4

Validate

Solution:

Emf = VBL

{I}={{VBL}}/{{R}}

Heat

={I}^{2} {R}={{V}^{2} {B}^{2} {L}^{2}}/{{R}}

Given

{V}^{1}=2 {V}

{{H}^{1}}/{{H}}=4

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