KVPY 2020-21 SA Exam Previous Papers

Question : 36 of 80

Marks: +1, -0

A closed 10 L vessel contains 1 L water gas (1 : 1 CO :

H_2

) and 9 L air (20%

O_2

by volume) at STP. The contents of the vessel are ignited. The number of moles of

CO_2

in the vessel is closest to:

Solution:

1 {L}

water gas has

1: 1 {CO}

and

{H}_{2}

gases
So,

V_{{H}_{2}}=V_{{CO}}=0.5 {L}

{V}_{{O}_{2}}={9 \×20}/{100}=1.8 {L}

Now, on ignition

\table 2 {CO}({g}),+,{O}_{2}({g}) ,\→ ,2 {CO}_{2}({g});0.5 L,, 1.8 L,, 0.5 L

at STP
∴ Number of moles of

CO_2

formed

={0.5}/{22.4}=0.022

moles

Go to Question:

Prev Question

Next Question