KVPY 2020-21 SA Exam Previous Papers

Question : 18 of 80

Marks: +1, -0

. A submarine has a window of area 30 × 30 cm

^{2}

on its ceiling and is at a depth of 100 m below sea level in a sea. If the pressure inside the submarine is maintained at the sea-level atmosphere pressure, then the force acting on the window is (consider density of sea water = 1.03 × 10

^{3}

kg/m

^{3}

, acceleration due to gravity = 10 m/s

^{2}

)

$0.93 × 10^5 N$
$0.93 × 10^3 N$
$1.86 × 10^5 N$
$1.86 × 10^3 N$

Validate

Solution:

Submarine is at 100 m below the sea level and pressure inside the submarine is at atmospheric pressure
So net force on the window
F = Gauge pressure × Area

=\ ρg h A=1.03 \×10^{3} × 10 \×100 \

×900 \×10^{-4} {N}

=1.03 \×10^{4} \×9 {N}

=9.27 \×10^{4} {N}

\≈0.93 \×10^{5} {N}

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