KVPY 2019 SB SX Exam Previous Papers

Question : 8 of 120

Marks: +1, -0

Let S be subset of the plane defined by

S = \{(x, y) : |x| + 2|y| = 1\}.

Then the radius of the smallest circle with centre at the origin and having non-empty intersection with S is

Solution:

1/2×√5/2×r=1/2×1×1/2

⇒

r=1/√5

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