KVPY 2019 SB SX Exam Previous Papers

Question : 19 of 120

Marks: +1, -0

Let a > 0, a ≠ 1. Then the set S of all positive real numbers b satisfying

(1 + a^2)(1 + b^2) = 4ab

Solution:

(1 + a^2 )(1 + b^2 ) = 4ab

⇒

(a+1/a)(b+1/b)=4

⇒ a = 1 and b = 1
but a ≠ 1 so no value of b

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