KVPY 2019 SB SX Exam Previous Papers

Question : 103 of 120

Marks: +1, -0

In the following reaction, P gives two products Q and R, each in 40% yield.

If the reaction is carried out with 420 mg of P, the reaction yields 108.8 mg of Q. The amount of R produced in the reaction is closest to

Solution:

Given
Moles =

{420 ×10^{-3}}/210

Let Moles of R produced =

{0.4×420 ×10^{-3}}/210×106 \g = 84.8 \mg

Mole of Q produced =

{0.4×420 ×10^{-3}}/210

Wt. of Q produced =

{0.4×420 ×10^{-3}}/210 × 136 \g = 108.8 \mg

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