KVPY 2019 SA Exam Previous Papers

Question : 74 of 80

Marks: +1, -0

An organic compound contains 46.78% of a halogen X. When 2.00 g of this compound is heated with fuming HNO

_3

in the presence of AgNO

_3

, 2.21 g AgX was formed. The halogen X is
[Given: atomic weight of Ag = 108, F = 19, Cl = 35.5, Br = 80, I = 127]

Solution:

A + \conc. HNO_3 + AgNO_3 \ {––––––––▸} AgX

Mass of halogen (x) =

2×46.78/100= 0.9356 \gram

Mass of

Ag^{+} = (2.21 -0.9356) = 1.2744

nAg = nX

= 1.2744/108=0.9356/M_x⇒M_x = 80

So halogen x is Bromine

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