KVPY 2019 SA Exam Previous Papers

Question : 23 of 80

Marks: +1, -0

A particle slides from the top of a smooth hemispherical surface of radius R which is fixed on a horizontal surface. If it separates from the hemisphere at a height h from the horizontal surface then the speed of the particle is :

$√(2g(R-h))$
$√(2g(R+h))$
$√ {2g R}$
$√ {2g h}$

Validate

Solution:

From work energy theorem

mg(R -h) = 1/2mv^2

v=√(2g(R-h))

Go to Question:

Prev Question

Next Question