In an oil drop experiment, ' n ' numbers of electrons are stripped from an oil drop to make it positively charged. A vertical electric field of magnitude 4.9 \times 10^{14} {\N} \/ {\C} is applied to balance the force due to gravity on the oil drop. If the mass of oil drop is 80 \mu {\g}, the value of ' n ' will be: (Take {\g}=9.8 {\m} \/ { s}^2 and charge of an electron =1.6 \times 10^{-19} {\C} )

KEAM 2023 Physics and Chemistry Solved Paper

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In an oil drop experiment, ' n ' numbers of electrons are stripped from an oil drop to make it positively charged. A vertical electric field of magnitude 4.9×1014N∕C is applied to balance the force due to gravity on the oil drop. If the mass of oil drop is 80µg, the value of ' n ' will be: (Take g=9.8m∕ s2 and charge of an electron =1.6×10−19C )

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