\int \sin ^2 \pi x \dx=

Correct Answer is : π2−14πsin2πx+C

\frac{\pi}{2}-\frac{1}{4 \pi} \sin 2 \pi x+C

\frac{\pi}{2}-\frac{1}{8 \pi} \sin 4 \pi x+C

\frac{x}{8}-\frac{1}{4 \pi} \sin 2 \pi x+C

x+\frac{1}{2 \pi} \sin 2 \pi x+c

\frac{x}{2}-\frac{1}{2 \pi} \cos 2 \pi x+C

KEAM 2023 Math Solved Paper

Question : 86 of 120

Marks: +1, -0

∫sin‌2πx‌dx=

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