If y=x^{e^x}+x^e for x>0, then \frac{d y}{d x} is equal to

Correct Answer is : xexex[1x+lnx]+exe−1

x^{e^x} [\frac{1}{x}+\ln x] +e^x

x^{e^x} e^x [\frac{1}{x}+\ln x] +e x^{e-1}

x^{e^x} e^{-x} [\frac{1}{x}-\ln x] +e x^{e-1}

x^{e^x} e^x [\frac{1}{n}-\ln x] +e x^{e-1}

KEAM 2023 Math Solved Paper

Question : 83 of 120

Marks: +1, -0

If y=xex+xe for x>0, then ‌

is equal to

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