Let \overrightarrow{a}=\stackrel{\^}{i}-\stackrel{\^}{j}+2 \stackrel{\^}{k}. Then the vector in the direction of \overrightarrow{a} with magnitude 5 units is

Correct Answer is : 1√16(5^i−5^j+10^k)

5 \stackrel{\^}{i}-5 \stackrel{\^}{j}+10 \stackrel{\^}{k}

-5 \stackrel{\^}{i}-5 \stackrel{\^}{j}+10 \stackrel{\^}{k}

{1}/{\sqrt{16}}(5 \stackrel{\^}{i}-5 \stackrel{\^}{j}+10 \stackrel{\^}{k})

{1}/{\sqrt{6}}(-5 \stackrel{\^}{\bo {i}}-5 \stackrel{\^}{\bo {j}}+10 \stackrel{\^}{\bo {k}})

{1}/{\sqrt{6}}(-10 \stackrel{\^}{ {\i}}-5 \stackrel{\^}{ {\j}}+5 \stackrel{\^}{ {\k}})

KEAM 2023 Math Solved Paper

Question : 64 of 120

Marks: +1, -0

Let

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−

. Then the vector in the direction of

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with magnitude 5 units is

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