Let (3+x)^{10}=a_0+a_1(1+x)+a_2(1+x)^2+\cdots a_{10}(1+x)^{10}, where a_1, a_2, \cdots a_{10} are constants. Then the value of a_0+a_1+a_2+\cdots a_{10} is equal to

KEAM 2022 Math Solved Paper

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Let (3+x)10=a0+a1(1+x)+a2(1+x)2+⋯a10(1+x)10, where a1,a2,⋯a10 are constants. Then the value of a0+a1+a2+⋯a10 is equal to

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