\int \frac{1}{x^3} \sqrt{1-\frac{1}{x^2}} \dx=

Correct Answer is : 43(1−1x2)32+C

\frac{-1}{6} (1-\frac{1}{x^2}) ^{\frac{3}{2}}+C

\frac{1}{3} (1-\frac{1}{x^2}) ^{\frac{3}{2}}+C

\frac{-1}{3} (1-\frac{1}{x^2}) ^{\frac{3}{2}}+C

\frac{4}{3} (1-\frac{1}{x^2}) ^{\frac{3}{2}}+C

\frac{-4}{3} (1-\frac{1}{x^2}) ^{\frac{3}{2}}+C

KEAM 2022 Math Solved Paper

Question : 34 of 120

Marks: +1, -0

∫‌

√1−‌

‌dx=

‌
−1
6
(1−‌
1
x2
)‌
3
2
+C
‌
1
3
(1−‌
1
x2
)‌
3
2
+C
‌
−1
3
(1−‌
1
x2
)‌
3
2
+C
‌
4
3
(1−‌
1
x2
)‌
3
2
+C
‌
−4
3
(1−‌
1
x2
)‌
3
2
+C

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