KEAM 2022 Math Solved Paper

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Question : 103 of 120

Marks: +1, -0

The equation of the circle touching the x-axis at (5,0) and the line y=10 is

x2+y2−10x−10y+25=0
x2+y2−10x−10y−25=0
x2+y2−5x−5y−5=0
x2+y2−5x−5y+5=0
x2+y2+10x+10y−25=0

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