KEAM 2021 Physics and Chemistry Solved Paper

Given, ‌‌h1=h
and h2=‌

h

4

Let m is the mass of the object.
Initial potential energy, Ui=mgh
Just before it strikes the ground, its initial potential energy is converted into kinetic energy.
⇒‌‌KE=Ui
When it rebounds to height h2, so final
PE=mgh2=‌

mgh

4

‌‌(∵h2=‌

h

4

)
So, the fraction of energy loss =‌

mgh− mgh 4

mgh

=‌

3

4