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Question : 32 of 120
Marks:
+1,
-0
Solution:
Since, vectors
α+(α−1)+3 and
(α+2+α−2 are perpendicular.
⇒α(α+2)+(α−1)α+3(−2)=0 ⇒‌‌α2+2α+α2−α−6=0 ⇒‌‌2α2+α−6=0 ⇒‌‌2α2+4α−3α−6=0 ⇒‌‌2α(α+2)−3(α+2)=0 ⇒(2α−3)(α+2)=0 ⇒α=−2,‌
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