KEAM 2021 Math Solved Paper

Slope of line segment joining the points (10,0) and (0,−4)
=‌

−4−0

0−10

=‌

4

10

=‌

2

5

Mid point of line segment joining the points (‌

10+0

2

,‌

0−4

2

)=(5,−2)
Let m be the slope of the required line.
m×‌

2

5

=−1⇒m=‌

−5

2

∴ Equation of perpendicular bisector of the line segment joining points
(y+2)=(−‌

5

2

)(x−5)
⇒‌‌2y+4=−5x+25
⇒‌‌5x+2y=21