KEAM 2020 Math Paper

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Question : 55 of 120

Marks: +1, -0

A circle with centre at (3,6) passes through (-1,1) . Its equation is

x2+y2−6x−12y+3=0
x2+y2+6x−10y+3=0
x2+y2−3x−6y+1=0
x2+y2+5x+9y+5=0
x2+y2−6x−12y+4=0

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