KEAM 2020 Math Paper

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Question : 118 of 120

Marks: +1, -0

The general solution of the differential equation xy′+y=x2,x>0 is

y=
x2
2
+Cx
y=
x3
3
+C
y=
x2
3
+C
y=
x3
3
+
C
x
y=
x2
3
+
C
x

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