KEAM 2019 Physics and Chemistry Paper

Two masses, m1 and m2 are hanging from a support as shown in figure.The tension in string BC
T1=( total mass hanging on string) g=m2g
Similarly, the tension in string OA
T2=( total mass hanging on string OA)‌g
T2=(m1+m2)g
Hence, the tension in the upper, string is
T=(m1+m2)g