KEAM 2019 Physics and Chemistry Paper

Given, initial velocity of vehicle u=36km/h
=10m/s
Stopping distance of vehicle s=5m and mass of vehicle m=2000kg
So, from equation of motion
v2−u2=2as
since, final velocity of vehicle v=0 and acceleration of vehicle =−a (acceleration)
⇒‌‌−u2=−2as
⇒‌‌a=‌

u2

2s

=‌

10×10

2×5

=10m/s2
The average force for braking
F=ma=2000×10=2×104N