KEAM 2019 Physics and Chemistry Paper

3 capacitors connected with a 6V battery as shown in the figure below∴ Equivalent capacitance of 1nf and 2nF connected in parallel is given as, C′=(1+2)nF
This equivalent C′ is connected in series with 3nF. So, the equivalent capacitance of the given circuit is
Ceq=‌

(1×2)×3

(1+2)+3

=1.5nF
Total charge on the capacitors =V×Ceq
=6×(1.5nF)=9nC