KEAM 2019 Physics and Chemistry Paper

Key Idea Kepler's law of periods states that the square of time period of revolution of a planet is proportional to cube of the semi-major axis of the ellipse traced out by the planet i.e.
T2∝R3
Given, semi-major axis of planets, RA=1AU and RB=5AU, and period of revolution of planet A,
TA=1yr
As, ⇒‌‌TB=√125=11.18yr
So, the near by option is (c).