KEAM 2019 Physics and Chemistry Paper

Magnitude of electric field is given as.
E=‌

F

q

where, F is the magnitude of the electrostatic force and q is the charge
Here, F=1N
and q=e=1.6×10−19C
⇒‌‌E=‌

1

e

N/C
Force experienced by a negative charge is in the opposite direction to the electric field. As, for a negatively charged particle, its electric field vector at each point is directed radially inwards.
Thus, the magnitude and direction of E is

1

e

N/C and
E and F are against each other.