KEAM 2019 Math Paper

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Question : 41 of 121

Marks: +1, -0

The equation of the curve that passes through the point (1,2) and satisfies ‌

dy

dx

=‌

−2xy

x2+1

is

y(x2+1)+2=0
y(x2+1)+1=0
y(x2+1)=4
y(x2+1)=2
y(x2−1)=2

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