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Question : 109 of 121
Marks:
+1,
-0
Solution:
Let
a=x++z a⋅=(x+y+z)⋅=x a⋅(+)=(x+y+z)⋅(+) =x+y and
a⋅(++)=(++z)⋅(++) =x+y+z It is given that,
a⋅=a⋅(+)=a⋅(++) ⇒x=x+y=x+y+z Taking,
x=x+y⇒y=0 x+y=x+y+z⇒z=0 x has any real values.
Now, take
x=1 ∴ a=
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