KEAM 2019 Math Paper

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Question : 106 of 121

Marks: +1, -0

Let f(x)=x2−x+1,x≥‌

1

2

, then the solution of the equation f(x)=f−1(x) is

x=1
x=2
x=‌
1
2
x=‌
1
3
4

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