KEAM 2018 Math Paper

© examsiri.com

Question : 87 of 120

Marks: +1, -0

The equation of the circle with centre (2, 2) which passes through (4, 5) is

x2+y2−4x+4y−77=0
x2+y2−4x+4y−5=0
x2+y2+2x+2y−59=0
x2+y2−2x−2y−23=0
x2+y2−4x−2y−26=0

Go to Question:

Prev Question

Next Question