KEAM 2018 Math Paper

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Question : 79 of 120

Marks: +1, -0

If

3

⋀

i

+2

⋀

j

−5

⋀

k

=x(2

⋀

i

−

⋀

j

+

⋀

k

)+y(

⋀

i

+3

⋀

j

−2

⋀

k

)+z(−2

⋀

i

+

⋀

j

−3

⋀

k

)

x=1,y=2,z=3
x=2,y=3,z=1
x=3,y=1,z=2
x=1,y=3,z=2
x=2,y=2,z=3

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