KEAM 2018 Math Paper

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Question : 48 of 120

Marks: +1, -0

A poison variate X satisfies P(X=1)=P(x=2).P(X=6) is equal to

4
45
e−2
1
45
e−1
1
9
e−2
1
4
e−2
1
45
e−2

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