Let f(x)=px^2+qx+r, where p, q, r are constants and p\neq0. If f(5)=-3f(2) and f(-4)=0, then the root of f is

KEAM 2018 Math Paper

Question : 14 of 120

Marks: +1, -0

Let f(x)=px2+qx+r, where p, q, r are constants and p≠0. If f(5)=−3f(2) and f(−4)=0, then the root of f is

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