KEAM 2017 Math Paper

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Question : 78 of 120

Marks: +1, -0

Let Δ =|

1	1	1
1	−1−w2	w2
1	w	w4

|, where w≠1 is a complex number such that w3=1. Then Δ equals

3w+w2
3w2
3(w=w2)
−3w2
3w2+1

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