KEAM 2016 Physics and Chemistry Paper

Given, radius of first capillary tube =r Height of nised liquid in first capillary tube =h Mass of liquid in first capillary tube =m
We know that.
or m∝π2h
m∝r2h
m= constant
So. h∝‌

1

r

⇒m∝r
Now, ‌

m2

m1

‌‌=‌

r2

r1

⇒‌‌‌

m2

m1

‌‌=‌

r2

r1

=2
m2‌‌=2m1‌ or ‌m2=2m
{∵m1=m}